State with reason which of the following are surds and which are not?
(i) √5×√10
(ii) √8×√6
(iii) √27×√3
(iv) √16×√4
(v) 5√8×2√6
(vi)√125×√5
(vii) √100×√2
(viii) 6√2×9√3
(ix)√120×√45
(x) √15×√6
Note: if
An irrational root of a rational number is a surd.
(i) √5×√10 =√5×√(5×2)= √5×√5×√2=5×√2
5√2 is an irrational number
Since, it cannot be expressed as ratio of two integers and value of √2 =1.414213562… which is non termination non repeating.
Thus √5×√10 is a surd.
(ii) √8×√6= √(4×2)×√(3×2)=√4 √2 √2 √3=2×2×√3=4√3
This is an irrational number.
Since, it cannot be expressed as ratio of two integers and value of √3=1.73205080… which is non termination non repeating.
Thus √8×√6 is a surd
(iii) √27×√3= √(9×3)×√3=3×√3×√3=3×3=9 which is a rational number. (9/1)
Since it can be represented in form p/q (p=9, q=1) where q≠0 and p;q have no common factor other than 1.
Thus √27×√3 is a not a surd.
(iv) √16×√4=4×2=8/1 which is a rational number.
Since, it can be represented in form p/q (p=8, q=1) where q≠0 and p;q have no common factor other than 1.
Thus √16×√4 is not a surd.
(v) 5√8×2√6=5√(4×2)×2√(3×2)=5×√4×√2×2×√3×√2
5×2×√2×2×√3×√2=40√3 is irrational
Since, it cannot be expressed as ratio of two integers and value of √3=1.73205080… which is non termination non repeating.
Thus 5√8×2√6 is a surd.
(vi) √125×√5= √(5×5×5)×√5= √(5×5) × √(5×5)=5×5=25/1 is a rational number
Since, it can be represented in form p/q (p=25, q=1) where q≠0 and p;q have no common factor other than 1.
Thus √125×√5 is not a surd.
(vii) √100×√2=10√2 is an irrational number
Since, it cannot be expressed as ratio of two integers and value of √2 =1.414213562… which is non termination non repeating.
Thus √100×√2 is a surd.
(viii) 6√2×9√3= 54√2×√3= 54√6 is an irrational number
Since, it cannot be expressed as ratio of two integers and value of √6 =2.449489742… which is non termination non repeating.
Thus 54√2 is a surd.
(ix) √120×√45= √(15×8)×√(15×3)=√15×√15×√(4×2)×√3
=15×2×√2×√3=30√6 is an irrational number
Since, it cannot be expressed as ratio of two integers and value of √6 =2.449489742… which is non termination non repeating.
Thus √120×√45 is a surd.
(x) √15×√6=√(5×3)×√(2×3)= √5×√2×√3×√3=3√10 is an irrational number
Since, it cannot be expressed as ratio of two integers and value of √10 = 3.16227766… which is non termination non repeating.
Thus √15×√6 is a surd.
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