The function ‘t’ which maps temperature in degree Celsius into temperature in degree Fahrenheit is defined by t(C) = + 32.
Find
(i) t(0)
(ii) t(28)
(iii) t(−10)
(iv) The value of C, when t(C) =212.

t(C) = + 32
(i) t(0) = + 32
          = 0 + 32 = 32
(ii) t(28) = + 32
            = + 32
            = 50.4 + 32
            = 82.4
(iii) t(−10) = + 32
               = -18 + 32
               = 14.
(iv) The value of C, when t(C) =212
212 = + 32
212 5 = 9C + 160
1060 – 160 = 9C
          900 = 9C
                 C= 100