Q1 of 11 Page 5

(i) (5i)       (ii) i9 + i19        (iii) i-39


(i) (5i)

= - 3i2

= -3(-1) = 3

= 3 + i0

(ii) i9 + i19

= i8.i + i18.i

= (i2)4i + (i2)9i

=(-1)4i + (-1)9i

= i - i = 0

= 0 + i0

(iii) i-39

= (i39)-1

= [i38.l]-1

= [(l2)19 i]-1

= [(-1)19 i]-1

= (-i)-1 =

= - = = = i = 0 + i(1)

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