Q27 of 40 Page 422

Evaluate:

Using cosec(90° - θ) = secθ


and cot(90° - θ) = tanθ


we have,




Now, sin(90 - θ) = cos θ and


tan(90 - θ) = cot θ we have




[ Since,


tan2θ - sec2θ = 1


sin2θ + cos2θ = 1


tan 60° = √3]


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Solve the following system of linear equations graphically:

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