Is it true that for any sets A and B, P (A) ∪ P (B) = P (A ∪ B)? Justify your answer.
Let us assume, A = {0, 1}
And, B = {1, 2}
∴ ![]()
Now, we have:
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∴ ![]()
Also, ![]()
∴ ![]()
Hence, the given statement is false
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