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9. Sequences and series
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Q7 of 97 Page 185

Find the sum to n terms of the A.P., whose kth term is 5k + 1.

Let the first term be a and common difference be d.


Given that kth term of the A.P. is 5k + 1.


kth term = ak = a + (k – 1)


∴ a + (k – 1)d = 5k + 1 ⇒ a + kd – d = 5k + 1


Comparing the coefficient of k, we obtain d = 5 and a – d = 1


⇒ a – 5 = 1


⇒ a = 6



Putting the value of a and d




∴


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Questions · 97
9. Sequences and series
1 2 3 4 5 6 7 8 9 10 11 12 13 14 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 21 22 23 24 25 26 27 28 29 30 31 32
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