Prove that -
(cos x - cos y)2 + (sin x - sin y)2 = 4 sin2[(x-y)/2]
We know that-
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L.H.S = (cos x - cos y)2 + (sin x - sin y)2

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= 4 sin2[(x-y)/2]×1 [∵ sin2x + cos2x = 1]
= 4 sin2[(x-y)/2]
= R.H.S
Hence, L.H.S = R.H.S…Proved
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