Q22 of 31 Page 1

A. For the complex write the hybridization, magnetic character and spin of the complex. (At. Number: Fe=26)

B. Draw one of the geometrical isomers of the complex which is optically active.

a) Theatomic number of Iron (Fe) is Z = 26


The electronic configuration of 26Fe= [Ar] 3d6 4s2


Oxidation number of Fe in [Fe(CN)6]4- is


Let oxidation number of Fe is x


⇒ x + (-1) × 6 = -4


⇒ x-6 = -4


⇒ x = -4 +6


⇒ x = 2


Thus, the electronic configuration of Fe2+=[Ar] 3d6


The formation of [Fe(CN)6]4- may be explained through hybridization as follows:



Hybridization: d2sp3


Magnetic character: Diamagnetic (no unpaired electrons)


Spin: Low spin (inner d-orbitals are used for the pairing)


b) The geometrical isomers of the complex [Pt(en)2Cl2]2+ which is optically inactive is given below



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