For the function
.Prove that f’ (1) =100 f’ (0).
Given function is



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At x = 0
f’(0) = 0 + 0 + … + 0 + 1
f’(0) = 1
At x = 1
f’(1) = 199 + 198 + … + 1 + 1 = [1 + 1 ….+ 1] 100 times = 1 × 100 = 100
Thus f’(1) = 100 f’(0)
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