There are two types of fertilisers F1 and F2. F1 consists of 10% nitrogen and 6% phosphoric acid and F2 consists of 5% nitrogen and 10% phosphoric acid. After testing the soil conditions, a farmer finds that she needs at least 14 kg of nitrogen and 14 kg of phosphoric acid for her crop. If F1 costs Rs 6/kg and F2 costs Rs 5/kg, determine how much of each type of fertiliser should be used so that nutrient requirements are met at a minimum cost. What is the minimum cost?
let the farmer buy x kf of fertilizer f1 and y kg of fertilizer f2
∴ x and y ≥ 0
The tabular representation of the data is as follows:

F1 consists of 10% nitrogen and F2 consists of 5% nitrogen. But the farmer requires at least 14 kg of nitrogen.
10% × x + 5% × y ≥ 14
![]()
2x+y ≥ 280
food F1 consists of 6% phosphoric acid and food F2 consists of 10% phosphoric acid. But the farmer requires at least 14kg of phosphoric acid
⇒ 6% × x + 10% of y ≥ 14
⇒ ![]()
3x + 56y ≥ 700
Total cost of fertilizers, Z= 6x+ 5y
The mathematical formulation of the given data is
Minimize, Z = 6x +5y
Subject to constraints
2x+y ≥ 280
3x + 56y ≥ 700
x and y ≥ 0
The feasible region determined by the system of constraint is:

It can be seen from the graph that the feasible region is unbounded
The corner points are ![]()
The value of Z at these points are:

As the feasible region is unbounded, 1000 may or may not be the minimum value
For this we will draw graph of inequality
6x+ 5y < 1000
It can be seen there is no common point between feasible region and 6x+ 5y < 1000
∴ 100 KG of fertilizer F1 and 80 kg of fertilizerF2 should be used to minimize the cost and the minimum cost is Rs 1000.
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.