Q7 of 23 Page 22

In figure 2.27, if line AB || line CF and line BC || line ED then prove that ABC = FDE

Given: Line AB CF and line BC ED

To find: ABC = FDE


Construction: G and h in diagram.


AB CD and BC is transversal both


So, ABC = PCG (linear pair angle)



BC ED and PF is transversal line to both


So, ECG = CDH


CD = FDE (Both angle is opposite)


ABC = FDE (hence proved)


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