Q4 of 21 Page 113

In right angled ΔLMN, if ∠N = θ, ∠M = 900, cosθ = 24/25 find sinθ and tanθ Similarly, find (sin2θ) and (cos2θ).

Give:

cosθ = 24/25


cosθ = Adjacent side/Hypotenuse


Adjacent side = 24


Hypotenuse = 25


By Pythagoras Theorem


Hypotenuse2 = Opposite side2 + Adjacent2


Opposite side2 = Hypotenuse2 - Adjacent2


= 252 - 242


= 625 – 576


= 49


Opposite side2 = 49


Opposite side = 7


sinθ = Opposite side/Hypotenuse


= 7/25


tanθ = sinθ/cosθ


= Opposite side/Adjacent side


= 7/24


sin2θ = (7/25)2


= 49/625


cos2θ = (24/25)2


= 576/625


More from this chapter

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1

Choose the correct alternative answer for following multiple choice questions.

 2

In right angled ΔTSU, TS = 5, ∠S = 900, SU =12 then find sin T, cos T, tan T. Similarly find sin U, cos U, tan U.

 3

In right angled ΔYXZ, ∠X = 900, XZ = 8cm, YZ =17cm, find sin Y, cos Y, tan Y, sin Z, cos Z, tan Z.

 5

Fill in the blanks.

i.


ii.


iii.