Solve the following problems.
When two resistors are connected in series, their effective resistance is 80 W. When they are connected in parallel, their effective resistance is 20 W. What are the values of the two resistances?
Given:
Effective resistance when two resistors are connected in series =
80Ω
Let us consider the resistances as R1 and R2
R1 + R2 = 80Ω ---(1)
Effective resistance when two resistors are connected in parallel = 20Ω
Effective resistance in case of parallel connection ![]()
Therefore
= 20Ω ---(2)
Solving eq(1) and eq(2)
![]()
![]()
R1R2 = 1600
(R1-R2)2 = (R1 + R2)2 - 4R1R2
= 802 - (4×1600)
= 0
R1-R2 = 0 ---(3)
Solving (1) and (3)
we get R1 = R2 = 40Ω
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.

