Q9 of 11 Page 44

Solve the following problems.

When two resistors are connected in series, their effective resistance is 80 W. When they are connected in parallel, their effective resistance is 20 W. What are the values of the two resistances?

Given:

Effective resistance when two resistors are connected in series =


80Ω


Let us consider the resistances as R1 and R2


R1 + R2 = 80Ω ---(1)


Effective resistance when two resistors are connected in parallel = 20Ω


Effective resistance in case of parallel connection


Therefore = 20Ω ---(2)


Solving eq(1) and eq(2)




R1R2 = 1600


(R1-R2)2 = (R1 + R2)2 - 4R1R2


= 802 - (4×1600)


= 0


R1-R2 = 0 ---(3)


Solving (1) and (3)


we get R1 = R2 = 40Ω


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