Two samples ‘m’ and ‘n’ of slaked lime were obtained from two different reactions. The details about their composition are as follows:
‘sample m’ mass: 7g
Mass of constituent oxygen: 2g
Mass of constituent calcium: 5g
‘sample n’ mass: 1.4g
Mass of constituent oxygen: 0.4g
Mass of constituent calcium: 1.0g
Which law of chemical combination does this prove? Explain.
Slaked lime = calcium hydroxide {Ca(OH)2}
The law of constant proportions states that “The proportion by weight of the constituent elements in the various samples of a compound is fixed,”
The proportion by weight of oxygen and calcium in slaked lime(in sample m) is 2:5 i.e. 0.4:1
The proportion by weight of oxygen and calcium in slaked lime(in sample n) is 0.4:1.0
Since the proportions of constituent elements remain fixed it follows the law of constant proportion.
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.