Q5 of 13 Page 127

Solve the following examples

An object of height 7 cm is kept at a distance of 25 cm in front of a concave mirror. The focal length of the mirror is 15 cm. At what distance from the mirror should a screen be kept so as to get a clear image? What will be the size and nature of the image?


According to the question,

Object distance (u) = -25 cm;


Height of object (Ho) = + 7 cm;


Focal length (f) = -15 cm;


Image distance = v cm;


By Mirror Formula:



1/v + 1/u = 1/f.


Putting values we get,





Taking the lcm, we get,





v = -37.5 cm


the image distance = 37.5 cm (The negative sign indicates that the image is formed on the left side of the mirror)


Now, image distance (v) = -37.5 cm


Magnification =


Hi is the image height.


HO is the object height.


“v” is the image distance


“u” is the object distance




Hi = -10.5 cm.


Size of image is 10.5 cm which is negative hence image is real .


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