In triangles ABC and DEF, AB = FD and ∠A = ∠D. The two triangles will be congruent by SAS axiom if
Given: ΔABC and ΔDEF, AB = FD and ∠A = ∠D

The two triangles will be congruent by SAS axiom if two sides including one angle of one triangle is equal to the another triangle.
Hence, AC = DE (As ∠A is between AB and AC)
Option B is correct.
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