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12. Heron’s Formula
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Q1 of 36 Page 117

Find the cost of laying grass in a triangular field of sides 50 m, 65 m and 65 m at the rate of Rs 7 per m2

a = 50, b = 65, c = 65

s = (a + b + c)/2


⇒ s = (50 + 65 + 65)/2 = 180/2 = 90.


Area(Δ) = √s(s-a)(s-b)(s-c)


⇒ Area(Δ) = √90(90-50)(90-65)(90-65)


⇒ Area(Δ) = √90×40×25×25


⇒ Area(Δ) = 1500m2


Cost of laying grass = Area(Δ)×Cost per m2


⇒ Cost of laying grass = 1500×7 = Rs.10500


More from this chapter

All 36 →
8

The cost of leveling the ground in the form of a triangle having the sides 51m, 37m and 20m at the rate of Rs 3 per m2 is Rs 918.

9

In a triangle, the sides are given as 11 cm, 12 cm and 13 cm. The length of the altitude is 10.25 cm corresponding to the side having length 12 cm.

2

The triangular side walls of a flyover have been used for advertisements. The sides of the walls are 13 m, 14 m and 15 m. The advertisements yield and earning of Rs. 2000 per m2 a year. A company hired one of its walls for 6 months. How much rent did it pay?

3

From a point in the interior of an equilateral triangle, perpendiculars are drawn on the three sides. The lengths of the perpendiculars are 14 cm, 10 cm and 6 cm. Find the area of the triangle.

Questions · 36
12. Heron’s Formula
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