If n(A) = 20, n(B) = 28 and n (A ∪ B) = 36 then n (A ∩ B) = ?
Given: n(A) = 20, n(B) = 28 and n (A ∪ B) = 36
As we know, n (A ∪ B) = n(A) + n(B) - n (A ∩ B)
⇒ n (A ∩ B) = 20 + 28 - 36
⇒ n (A ∩ B) = 48 - 36
⇒ n (A ∩ B)) = 12
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