Q4 of 9 Page 32

The radius of a circle is 5 cm. The distance of a chord from the centre is 4 cm. Find the length of the chord.

Given: radius of a circle = 5cm

Distance of chord from centre = 4cm


By, Given information we will draw a circle



Given, radius PB = 5cm


PC = 4cm where, P is perpendicular bisector of segAB


Thus, ∠PCB = 90°


By Pythagoras formula


PB2 = BC2 + PC2


52 = BC2 + 42


25 = BC2 + 16


BC2 = 25 - 16 = 9cm


BC = √9 = 3cm


Since, P is perpendicular bisector of seg AB


Therefore, BC = CA = 3cm


Therefore, BA = BC + CA


BA = 3 + 3 = 6cm


Thus, length of a chord BA = 6cm


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