Using the measures given in the figure below, find the area of □EFGH.

Given:
GF = 50 m
GH = 34 m
HF = 52 m
Semi perimeter of Δ GHF = ![]()
According to Heron’s formula
Area of the triangle = √(s(s-a)(s-b)(s-c))
⇒ Area of the triangle Δ GHF = 816 sq m
Given:
HE = 20 m
EF = 48 m
HF = 52 m
Semi perimeter of Δ EHF = ![]()
According to Heron’s formula
Area of the triangle = √(s(s-a)(s-b)(s-c))
⇒ Area of the triangle Δ EHF = 480 sq m
Area of EFGH = Area of the triangle Δ GHF + Area of the triangle Δ EHF = 1296 sq m
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