Factorise:
2x2 – 7x – 15
2x2 – 7x – 15
The product of 1st and the 3rd term i.e. 30 can be factorized such that the sum or difference should be equal to the middle term.
Thus, the possible factors of 30 are 3 and 10
⇒ 2x2 – 10x + 3x – 15
⇒ 2x(x – 5) +3(x – 5)
⇒ (2x+3) (x – 5)
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