Q1 of 62 Page 157

Divide the first polynomial by the second. Explain the steps.

21b; 4

The division is as follows:



Here when 7 is multiplied by 3b we get 21b as the result.


In division the sign of the product [divisor × quotient] is always inverted to get the final result.


So the sign of product should always be opposite to that of the dividend.


So 21b becomes perfectly divisible by 7 and hence the quotient is 3b and remainder is 0.


More from this chapter

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1

Complete the following statements by filling in the blanks.

(1) 21 ÷ 7 … ∵ 21 = 7 × 3


(2) 45 ÷ 15 = …. ∵ 45 …… × ……


(3) We continue to carry out division until we get remainder zero or a whole number less than the ………….


(4) Dividend = division × (….) + (….), 0 ≤ remainder < divisor


(5) When we divide 43 by 5, the quotient is ………… and the remainder is ……….


Here, dividend = ………., divisor = ………


∴ 43 = 5 × …… + ……


(6) 2y × ……… = 10y2


(7) 5x × ……… = 15x4


(8) m2 × ……… = 9m4


(9) 3m × ………… = 9m4+

 1

Divide the first polynomial by the second. Explain the steps.

36p2; 6p

 1

Divide the first polynomial by the second. Explain the steps.

5a3; a3

 1

Divide the first polynomial by the second. Explain the steps.

–30n2; 3n