Q6 of 53 Page 91

Find the value of ‘n’ in each of the following:

(−3)n+1 × (−3)5 = (−3)−4

Given, (−3)n+1 × (−3)5 = (−3)−4

(3)n+1+5 = (−3)−4


(3)n+6 = (−3)−4


Comparing powers of (3), we get


n+6 = 4


n = 4 6


n= 10


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