In a laboratory the count of bacteria in a certain experiment was increasing at the rate of 2.5% per hour. Find the bacteria at the end of 2 hours if the count was initially 5, 06,000
Principal (P) = 506000
Rate of interest (R) = 2.5%
Time period (n) = 2hours
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= 506000×1.0252
= 531616.25
∴ The number of the bacteria at the end of 2 hours is 531616(approximately)
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