Q12 of 48 Page 408

If x + y + z = 6 and z is an odd digit, then the three-digit number xyz is

Since the sum of the digits of xyz i.e x + y + z = 6

∴ By divisibility test of three the number xyz is divisible by 3.


Also the last digit (z) is odd digit.


∴ xyz is the odd multiple of three.


Hence the option (a) is correct.

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