A letter is chosen from English alphabet. Find the probability of the letters being
a) A vowel
b) a letter comes after P
c) A vowel or a consonant
d) Not a vowel
Here sample space consist of 26 alphabets. So total number of possible outcomes = 26
Out of these a, e, i , o and u are vowels , ∴ number of vowels are 5
And remaining 21 alphabets are consonants.
a) let E be the event of drawing a vowel
then, P (E) = ![]()
b) There are q, r, s ,t , u, v, w , x ,y, z alphabets which comes after letter P.
The number of alphabets to come after p = 10
And let F be the event of drawing a letter which comes after P
P (F) = ![]()
(c) Since English alphabets consist of vowels or a consonant
The possibility of drawing a vowel or a consonant will be sum of probability of both the events happening equally likely
⇒ ![]()
Which is also the probability of a sure event.
(d) the consonant in English alphabets are b, c, d , f, g, h, , j , k ,l , m ,n, p, q , r ,s ,t ,v, w, x, y, z
The number of consonant are = 21
Let E be the event of drawing a consonant
Then P ( E) = ![]()
Couldn't generate an explanation.
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