Q1 of 50 Page 18

If A and B are two sets and U is the universal set such that n() = 700, n(A) = 200, n(B) = 300 and n (A B) = 100,find n(A’ B’).

Here we are provided with the cardinality of two sets A and B with and a universal set U and the cardinality of intersection of both the sets A and B is also provided.


The cardinality of the sets are as follows,


n(U) = 700


n(A) = 200


n(B) = 300


n(A B) = 100


From De Morgan’s Law we know that if U is an universal set and it contain two set named A and B then,


n(A’ B’) = n(A B)’ …(I)


To find the value of n(A' B') we first we have to find the value of (A U B)'.


We know that when the cardinality of two sets and the cardinality of their intersection is given we can find the cardinality of their union using the formula given below,


n(A B) = n(A) + n(B) –n(A B)


When we have the cardinality of union of two set the cardinality of their union difference (A U B)' can be found using the formula below


n(A B)’ = n(U) – n(A B)


*(A U B)' show the elements which are only the part of the universal set U and doesn’t exist in (A U B).


So using formula and putting values,


n(A B) = n(A) + n(B) –n(A B)


= 200 + 300 – 100


= 500 – 100


= 400


and n(A B)’ = n(U) – n(A B)


= 700 – 400


= 300


So putting these values in eqn (i) we will find


n(A’ B’) = n(A B)’


n(A' B') = 300


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