Construct a Δ PQR in which the base PQ = 6 cm, ∠R = 60° and the altitude from R to PQ is 4 cm.

Steps for construction:

Step 1: Draw a line segment PQ = 6 cm

Step 2: At A, make ∠QPX = 60°.

Step 3: Draw PY⊥PX.

Step 4: Draw the perpendicular bisector of PQ which meets PY at O.

Step 5: With O as center and OP as radius draw a circle.

Step 6: On the perpendicular bisector MO, mark a point S such that MS = 4cm.

Step 7: Draw RSR’ parallel to PQ meeting the circle at R and at R’.

Step 8: Complete DPQR which is one of the required triangles.