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1. Real Numbers
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Q4 of 18 Page 11

Given that HCF (306, 657) = 9, find LCM (306, 657).

HCF of (306, 657) = 9


We know that,


LCM×HCF = product of two numbers


LCM×HCF = 306×657


LCM =


LCM = 22338


More from this chapter

All 18 →
2

Find the LCM and HCF of the following pairs of integers and verify that LCM × HCF =

product of the two numbers.


(i) 26 and 91


(ii) 510 and 92


(iii) 336 and 54

3

Find the LCM and HCF of the following integers by applying the prime factorisation method.

(i) 12, 15 and 21


(ii) 17, 23 and 29


(iii) 8, 9 and 25

5

Check whether 6n can end with the digit 0 for any natural number n.

6

Explain why 7 × 11 × 13 + 13 and 7 × 6 × 5 × 4 × 3 × 2 × 1 + 5 are composite numbers.

Questions · 18
1. Real Numbers
1 2 3 4 5 1 2 3 4 5 6 7 1 2 3 1 2 3
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