Suppose that 1l of water is heated for a certain time to rise and its temperature by 2oC. If 2l of water is heated for the same time, by how much will its temperature rise? (AS7)
We know that: -
Q = mS∆T
⇒ ∆T = ![]()
⇒∆T is inversely proportional to the heat supplied.
⇒If the mass is greater than we get a change in temperature for the same amount of heat supplied.
Given the change in temperature when 1l(m1) of water is heated for a certain time = ∆T1 = 2oC
Let the change in temperature when 2l(m2) of water is heated for a certain time be ∆T2
Heat supplies and specific heat is constant for both the cases.
∴ ![]()
⇒ ![]()
⇒ ∆T2 = ![]()
⇒∆T2 = 1 oC
Hence, if 2l of water is heated for the same time then 1 of temperature rise will take place.
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.