Balance the following chemical equations. (AS1)

KClO₃KCl + O₂

KClO₃KCl + O₂

Balanced equation: 2KClO₃2KCl + 3O₂

Explanation:

⇒Step 1: Write the given unbalanced equation

KClO₃KCl + O₂

⇒Step 2: Compare the number of atoms of reactants with the number of atoms of products.

⇒Step 3: Now, first we consider the element having unequal no. of atoms on both sides. Thus, let us consider oxygen atom. If we multiply 2 in the product (in KClO₃) and 3 in the reactant (in O₂) we will get the equal number of atoms in both sides.

⇒Step 4: Write the resulting equation:

2KClO₃KCl + 3O₂

⇒Step 5: Now check whether the equation is balanced or not by comparing the atoms

We find that the equation is not balanced yet. As the number of potassium and chlorine atoms are unequal on the two sides. First balance the potassium atom.

⇒Step 6: If we multiply 2 in the product (in KCl), we will get the equal number of atoms as in reactant (in 2KClO₃)

⇒Step 7: Write the resulting equation:

2KClO₃2KCl + 3O₂

⇒Step 8: Now check whether the equation is balanced or not by comparing the atoms.

We find that the equation is balanced now.

⇒Step 9: Write down the final balanced equation:

2KClO₃2KCl + 3O₂