The absolute refractive index of water is 4/3. What is the critical angle? (AS1)
Given;
Absolute refractive index of water (n) = ![]()
By Snell’s Law critical angle(c) is given by =
(sin
inverse of
)
⇒ c = ![]()
⇒ c = ![]()
∴ c = 48.5o. (y looking in sine table).
Hence the critical angle is
or 48.5o.
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