Q8 of 12 Page 92

Solve the following examples.

5 cm high object is placed at a distance of 25 cm from a converging lens of focal length of 10 cm. Determine the position, size and type of the image.

As per the given information


Height of the object is 5 cms


Focal length f is 10 cms


Object distance u = 25 cms


Image distance v= ?


Height of the image h = ?


⇒


⇒


⇒



V = 50/3 =16.66 cms


The image formed will be real and inverted on the other side of the lens at a distance of 16.66 cms from its optical centre.


Now


m= v/u



Where h2 is the height of the object




⇒ h2 = 3.33cms


Therefore from above we can conclude an inverted image of 3.33cm will be formed.


More from this chapter

All 12 →
7

What are the function of iris and the muscles connected to the lens in the human eye?

 8

Solve the following examples.

The doctor has prescribed a lens having power +1.5 D. What will be the focal length of the lens? What is the type of the lens and what must be the defect of vision?

 8

Solve the following examples.

Three lenses having power 2, 2.5 and 1.7 D are kept touching in a row. What is the total power of the lens combination?

 8

Solve the following examples.

An object kept 60 cm from a lens gives a virtual image 20 cm in front of the lens. What is the focal length of the lens? Is it a converging lens or diverging lens?