The centre of the circle below is the origin and A, B are points on it.

Calculate the length of the chord AB.

Let coordinates of A be (x1,y1) and coordinates of B be(x2,y2).
Drop a perpendicular from A on X – axis intersecting X axis at P.
Now,
In Δ OPA
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And
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⇒ x1 = √3
∴ coordinates of A = (√3
)
Drop a perpendicular from B on X – axis intersecting X axis at Q.
Now,
In Δ OQB
![]()
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And
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∴ coordinates of B = (– 1,√3)
Hence, length of the chord AB =
The distance between point A and B =
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= √8 = √2
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