Q3 of 21 Page 75

Prove that Use this to compute correct to two decimal places.

(√2 + 1) (√2 – 1) = (√2)2 – (1)2 [ (a+b)(a-b) = a2-b2]


(√2 + 1) (√2 – 1) = 2 – 1


(√2 + 1) (√2 – 1) = 1


Hence, (√2 + 1) (√2 – 1) = 1


Now,







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