Prove that
Use this to compute
correct to two decimal places.
(√2 + 1) (√2 – 1) = (√2)2 – (1)2 [∵ (a+b)(a-b) = a2-b2]
⇒ (√2 + 1) (√2 – 1) = 2 – 1
⇒ (√2 + 1) (√2 – 1) = 1
Hence, (√2 + 1) (√2 – 1) = 1
Now,



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