In the picture below, the diagonals of the trapezium ABCD intersect at P.

Prove that PA × PD = PB × PC
Here AB, CD are parallel, then draw a line parallel to AB or CD through P.

Then,
We know that ,
Any three parallel lines will cut any two lines into pieces whose lengths are in the same ratio.
Therefore, ![]()
PA×PD = PB×PC
For verification, we can take a small trapezium and prove it as follows:

Here 3.8×2.12 = 7.98 = 1.9×4.25 approximately
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