When ammonia reacts with hydrogen chloride gas, it produces white fumes of ammonium chloride. The volume occupied by NH3 in glass bulb A is three times more than the volume occupied by HCl in glass bulb B at STP.

i) How many moles of ammonia are present in glass bulb A?
ii) How many grams of NH4Cl will be formed when the stopper is opened?
(Atomic mass of N = 14, H = 1, Cl = 35.5)
iii) Which gas will remain after completion of the reaction?
iv) Write the chemical reaction involved in this process.
(i) 3 moles
(ii) 53.5 grams (14 + 4 + 35.5)
(iii) Ammonia ( 2 moles will be remaining )
(iv) NH3 + HCl
NH4Cl
Explanation -1 mole of any gas at STP occupies 22.4 litres of volume. So, 1 mole of ammonia occupies 22.4 litres of volume. 67.2 litres (22.4 x 3) of volume is 3 moles of ammonia. 22.4 litres of HCl is 1 mole of HCl. According to reaction ,1 mole of ammonia reacts with 1 mole of HCl to form 1 mole of NH4Cl, which comes out as white fumes.
NH3 + HCl
NH4Cl
Even though 3 moles of ammonia is present in bulb, only one 1 mole undergoes reaction with 1 mole of HCl. The other 2 moles of ammonia remain unreacted.
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