Q3 of 46 Page 271

Find the total current that passes through the circuit given in the diagram. Also find the potential difference across 1Ω resistor.

To find the total current(I) passing through the circuit, we must find the total resistance(R) and also we know the battery’s potential difference(V) which is 1.5 V , so by Ohm’s law we can find the net current flowing in the circuit.

As we can see by the figure that two resistors 1 ohm and 2 ohm are in series to each other, so we can directly add them , 1 + 2 = 3 ohm,


Also we can see that 3 resistors 4 ohm , 6 ohm , and 12 ohm are parallel to each other , so , let the net parallel resistance of these three resistors be Rp ,



Therefore, Rp = 2 ohm


Hence by Ohm’s law, V = I× R



As the current passing through 1 ohm resistor is the net current flowing in the circuit, so


V = I× R = 0.75× 1 = 0.75 V. It is the potential difference(V) across the 1 ohm resistor.


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