Q5 of 58 Page 37

A train travelling at a speed of 90 kmph. Brakes are applied so as to produce a uniform acceleration of ‒0.5 ms-2. Find how far the train will go before it is brought to rest?

Given: speed(s) = 90 kmph


Acceleration = ‒0.5 ms-2


Distance travelled = ?


We use 3rd equation of motion to find the distance travelled


We have, speed(s) = 90 kmph


= 90 m/s


= 25 m/s


Acceleration = ‒0.5 ms-2


Final speed = 0 m/s






So train will travel 625m before it comes to rest.


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