The coordinates of the vertices of a quadrilateral are (2, 1), (5, 3), (8, 7), (4, 9) in order.
i) Find the coordinates of the midpoints of all sides.
ii) Prove that the quadrilateral with these midpoints as vertices is a parallelogram.
Let the mid points be A, B, C, D
Using the section formula for mid points
A(x, y)![]()
A(x, y)![]()
A(x, y) = (3.5,2)
B(x, y)![]()
B(x, y)![]()
B(x, y) = (6.5,5)
C(x, y)![]()
C(x, y)![]()
C(x, y) = (6,8)
D(x, y)![]()
D(x, y)![]()
D(x, y) = (3,5)
(ii) Length AB = √((6.5 - 3.5)2 + (5 - 2)2)
Length AB = 3√2 units
Length BC = √((6.5 - 6)2 + (5 - 8)2)
Length BC = √9.25 units
Length CD = √((6 - 3)2 + (8 - 5)2)
Length CD = 3√2 units
Length DA = √((3.5 - 3)2 + (2 - 5)2)
Length DA = √9.25 units
Since the lengths of opposite sides are equal hence it forms a parallelogram.
Hence the quadrilateral forms a parallelogram by joining the mid points .
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