The sum of three consecutive natural numbers is 36. What are the numbers?
Let the three consecutive natural numbers be x,x + 1,x + 2.
Their sum = 36
⇒ x + x + 1 + x + 2 = 36
⇒ 3x + 3 = 36
⇒ 3x = 36-3
⇒ 3x = 33
⇒![]()
⇒ x = 11
Hence, the required three consecutive numbers are 11 ,11 + 1,11 + 2 = 11,12 and 13.
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