Q2 of 7 Page 84

When acidified copper sulphate solution is electrolyzed oxygen is obtained at the anode. What arrangements are to be made for this? Find the element deposited at the cathode.

Take copper sulphate (CuSO4) in a beaker. Add some acid (H2SO4) to it and make a copper solution. Immerse two carbon rods in a beaker. Connect a battery to the rods. Oxidation occurs at anode and reduction occurs at the cathode. And we can observe that oxygen is produced at the anode.

4OH-(aq) 2H2O(l) + O2(g) + 4e-


Or H2O(l) 4H+(aq) + O2(g) + 4e-


And at cathode, copper will deposit due to conversion of Cu2+ ions to Cu.


Cu2+(aq) + 2e- Cu(s)


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