Q5 of 50 Page 43

An object of height 6 cm is placed at a distance of 15cm from concave mirror of focal length 10cm.Find the position nature and height of an image.

According to the question;

Object distance (u) = - 15 cm;


Focal length (f) = - 10 cm Image distance = v cm;


Height of object = 6 cm;


By Mirror Formula;



⇒ .


⇒


⇒


⇒ V = - 30 cm.


Since image distance v is negative


∴ Image is real and inverted.


Magnification (m) =


⇒


⇒


∴ Height of image = 12 cm.


∵ v > u ⇒ Magnification > 1 hence image is magnified.


A real, inverted and magnified image of height 12 cm is formed 30 cm in front of the mirror beyond centre of curvature.


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