A bridge across a valley is h metres long. There is a temple in the valley directly below the bridge. The angles of depression of the top of the temple from the two ends of the bridge have measures α and β. Prove that the height of the bridge above the top of the temple is 
Let AD be the bridge and E be the top of the temple.

The perpendicular from E on AD is EF.
Thus, EF represents the height from the top of the temple to the bridge.
Let EF = x and DF = y
AF = h – y
In ∆ABE,
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………(1)
In ∆DCE,
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………..(2)
From (1) and (2),
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h tan α tan ß – x tan ß = x tan α
h tan α tan ß = x(tan α + tan ß)
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The height of the bridge above the top of the temple is
.
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. On walking 192 metres towards the tower, the tangent of the angle is found to be
. Find the height of the tower.