Construct the following with the help of straight-edge and compass only:
Construct a triangle with sides 4 cm, 5 cm, 7 cm and then construct a triangle similar to it whose sides have lengths in the ratio 2 : 3 to the lengths of the corresponding sides of the first triangle.
Steps of Construction:
1.Draw triangle ABC of given dimensions.
2. Draw a ray AX making an acute angle with AB.
3. We have to construct triangle having ratio of 2:3. So we make 3 equal arcs on ray AX.
4. Taking A as center, cut an arc on ray AX. Mark the point as A1.
5. Now, with the same radius cut an arc on AX with A1 as center.
6. Mark till A3.
7. Join A3 with B.
8. As we have to divide in 2:3, we draw a line from A2 parallel to A3B.
9. The point where it cuts AB is P.
10. From P, draw a line parallel to BC.
11. APQ is the required triangle.
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.
times the lengths of the corresponding sides of ΔPQR.
ABC = 90, BC = 4 cm and AC = 5 cm. Then construct ΔBXY, where scale factor is 
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