A coin is tossed three times. Find the probability of the following events:
(1) A: getting at least two heads,
(2) B: getting exactly two heads,
(3) C: getting at most one head,
(4) D: getting more heads than tails.
If a coin is tossed three times their will be 8 outcomes.
HHH, HHT, HTH, TTH,HTT, THT, THH, TTT
Now, favourable outcomes of event A i.e, getting at least two heads are HHH,HHT,HTH,THH
Number of favourable outcomes of event A = 4
Now, favourable outcomes of event B i.e, getting exactly two heads are HHT,HTH,THH
Number of favourable outcomes of event B = 3
Now, favourable outcomes of event C i.e, getting at most one head are TTH,HTT,THT,TTT
Number of favourable outcomes of event C = 4
Now, favourable outcomes of event D i.e, getting more heads than tails are HHH,HHT,HTH,THH
Number of favourable outcomes of event D = 4
Total number of outcomes = 8
(i) Probability of occurrence of event A = P(A)
P(A) =
= 0.5
(ii) Probability of occurrence of event B = P(B)
P(B) =
= 0.375
(iii) Probability of occurrence of event C = P(C)
P(C) =
= 0.5
(iv) Probability of occurrence of event D = P(D)
P(D) =
= 0.5
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