Q8 of 19 Page 302

A coin is tossed three times. Find the probability of the following events:

(1) A: getting at least two heads,


(2) B: getting exactly two heads,


(3) C: getting at most one head,


(4) D: getting more heads than tails.

If a coin is tossed three times their will be 8 outcomes.

HHH, HHT, HTH, TTH,HTT, THT, THH, TTT


Now, favourable outcomes of event A i.e, getting at least two heads are HHH,HHT,HTH,THH


Number of favourable outcomes of event A = 4


Now, favourable outcomes of event B i.e, getting exactly two heads are HHT,HTH,THH


Number of favourable outcomes of event B = 3


Now, favourable outcomes of event C i.e, getting at most one head are TTH,HTT,THT,TTT


Number of favourable outcomes of event C = 4


Now, favourable outcomes of event D i.e, getting more heads than tails are HHH,HHT,HTH,THH


Number of favourable outcomes of event D = 4


Total number of outcomes = 8


(i) Probability of occurrence of event A = P(A)


P(A) = = 0.5


(ii) Probability of occurrence of event B = P(B)


P(B) = = 0.375


(iii) Probability of occurrence of event C = P(C)


P(C) = = 0.5


(iv) Probability of occurrence of event D = P(D)


P(D) = = 0.5


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