Q3 of 19 Page 54

PQR is a triangle right angled at P. If PQ = 10 cm and PR = 24 cm, find QR.

Given in a right-angled ΔPQR, ∠P = 90°, PQ = 10 cm and PR = 24 cm.


We know that in a right-angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.


⇒ In ΔPQR, QR2 = PQ2 + PR2


⇒ QR2 = 102 + 242


= 100 + 576


= 676


∴ QR = √676 = 26 cm


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