If the pair of equations 2x + 3y = 7; (a + b)x + (2a – b)y = 21 has infinitely many solutions then find the values of a, b.
Given, 2x + 3y = 7; (a + b)x + (2a – b)y = 21
We know that a pair of linear equations has infinitely many solutions
when,
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Here, a1 = 2, b1 = 3, c1 = 7
and a2 = (a + b), b2 = (2a – b), c2 = 21
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A + b = 6 …(i)
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2a – b = 9 …(ii)
Adding both the equations we get,
3a = 15
∴a = 5
∴b = 6 – 5
b = 1
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