Q3 of 12 Page 164

Two concentric circles are of radii 5 cm and 3 cm. Find the length of the chord of the larger circle which touches the smaller circle.

Given:

Radius of larger circle = 5 cm.


Radius of smaller circle = 3 cm.


Solution:


The diagram for the question is as follows:



AB is a tangent for smaller circle, and we know that tangent at any point is perpendicular to the radius through point of contact.


Hence, OP AB


Also, AB is a chord for large circle, and we know perpendicular from center to the chord bisects the chord


Hence,



Now, In ΔOAP


By Pythagoras theorem,


OA2 = AP2 + OP2


AP2 = OA2 – OP2


Here, OA = radius of bigger circle = 5 cm


and OB = radius of smaller circle = 3 cm


AP2 = 52 – 32


AP2 = 25 – 9


AP2 = 16


AP = 4 cm


Hence,


AB = 2 AP


= 2(4) = 8 cm


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