The area of circular field is 154 sq cm. Let us write by calculating the perimeter and area of circumference circular field with square.

Given: Area of circle = 154 cm2
We know that
Area of a circle = πr2
⇒ πr2 = 154
![]()
⇒ r2 = 7× 7
⇒ r = 7 cm
Also, Diameter of the circle = 2× radius
⇒ CE = 2× 7 = 14 cm
This acts as the diagonal of the inscribed square.
So, the diagonal of the square BCDE= 14 cm
Let the side of the square be x cm
We know that each angle of a square is 90°.
Using Pythagoras theorem,
CD2 +DE2 = CE2
⇒x2+ x2 = 142
⇒ 2x2 = 196
⇒x2 =98
Side of the square =7√2 cm
We know that Area of a Square = side× side
⇒ Area of BCDE =98 cm2
Perimeter of a square = 4× side
⇒ Perimeter of BCDE = 4× 7√2 = 28√2 cm
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.

